3=0
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WorldIsMine
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- Joined: 18 Mar 2014, 19:46
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Re: 3=0
uno just wanted to draw a bemis.
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WorldIsMine
- Standard Member
- Posts: 402
- Joined: 18 Mar 2014, 19:46
-
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WorldIsMine
- Standard Member
- Posts: 402
- Joined: 18 Mar 2014, 19:46
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belsammael
- Veteran Member
- Posts: 12841
- Joined: 13 May 2007, 21:44
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Re: 3=0
There is no error! All steps are legitimate. They're simple mathematical operations like division, multiplication etc.
It even excluded x which is 0 in the beginning, so no one can claim that there was division by 0, which would be an error.
WE MUST ACCEPT THE CONCLUSION! IT HAS BEEN PROVEN NOW!!!
It even excluded x which is 0 in the beginning, so no one can claim that there was division by 0, which would be an error.
WE MUST ACCEPT THE CONCLUSION! IT HAS BEEN PROVEN NOW!!!
Re: 3=0
The 2nd step takes a leap and changes the formula based on a different first step that did not take place.
In other words the 2nd step is not math at all. You cannot use two different 1st steps in algebra to arrive at a 2nd step contrive from both.
Algebra follows a logical sequence to arrive at the correct answer. Which means two 1st steps cannot be taken to arrive at a 2nd step. Use must use one or the other 1st step.
The formula just proves math can be done wrong which occurs often and therefore you arrive at an incorrect conclusion.
In other words the 2nd step is not math at all. You cannot use two different 1st steps in algebra to arrive at a 2nd step contrive from both.
Algebra follows a logical sequence to arrive at the correct answer. Which means two 1st steps cannot be taken to arrive at a 2nd step. Use must use one or the other 1st step.
The formula just proves math can be done wrong which occurs often and therefore you arrive at an incorrect conclusion.
Re: 3=0
[mention=705]Tearmoon[/mention]
If you have a set of two equations you can substitute the variable from the first one to the second one, right?
Like e.g. here: https://www.purplemath.com/modules/systlin4.htm
And you can just use the same equation twice. It's not an error.
In other words, you start with a set of two equations which happen to be identical:
x^2 + x + 1 = 0
x^2 + x + 1 = 0
(The two equations cannot be contradictory, because it's the same equation and an equation cannot contradict itself.)
You divide the first equation by x (x is not 0).
x + 1 + 1/x = 0
x^2 + x + 1 = 0
You find x from the second equation.
x + 1 + 1/x = 0
x = - x^2 - 1
And you substitute.
-x^2 - 1 + 1 + 1/x = 0
-x^2 + 1/x = 0
The next steps as in the post above.
So there is no problem at all.
If you have a set of two equations you can substitute the variable from the first one to the second one, right?
Like e.g. here: https://www.purplemath.com/modules/systlin4.htm
And you can just use the same equation twice. It's not an error.
In other words, you start with a set of two equations which happen to be identical:
x^2 + x + 1 = 0
x^2 + x + 1 = 0
(The two equations cannot be contradictory, because it's the same equation and an equation cannot contradict itself.)
You divide the first equation by x (x is not 0).
x + 1 + 1/x = 0
x^2 + x + 1 = 0
You find x from the second equation.
x + 1 + 1/x = 0
x = - x^2 - 1
And you substitute.
-x^2 - 1 + 1 + 1/x = 0
-x^2 + 1/x = 0
The next steps as in the post above.
So there is no problem at all.